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Jul 2, 2025
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fix(doc):minor-issues#2132 #2133

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10 changes: 5 additions & 5 deletions website/docs/List.mdx
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Original file line number Diff line number Diff line change
Expand Up @@ -186,7 +186,7 @@ update<R>(updater: (value: this) => R): R`}

<Repl
defaultValue={`const list = List([ 'a', 'b', 'c' ])
const result = list.update(2, val => val.toUpperCase())
list.update(2, val => val.toUpperCase())
// List [ "a", "b", "C" ]`}
/>

Expand Down Expand Up @@ -402,7 +402,7 @@ zip<U, V>(other: Collection<unknown, U>, other2: Collection<unknown, V>): List<[
<Repl
defaultValue={`const a = List([ 1, 2, 3 ]);
const b = List([ 4, 5, 6 ]);
const c = a.zip(b); // List [ [ 1, 4 ], [ 2, 5 ], [ 3, 6 ] ]`}
a.zip(b); // List [ [ 1, 4 ], [ 2, 5 ], [ 3, 6 ] ]`}
/>

<MemberLabel label="zipAll()" />
Expand All @@ -419,7 +419,7 @@ zipAll<U, V>(other: Collection<unknown, U>, other2: Collection<unknown, V>): Lis
<Repl
defaultValue={`const a = List([ 1, 2 ]);
const b = List([ 3, 4, 5 ]);
const c = a.zipAll(b);`}
a.zipAll(b);`}
/>

Note: Since zipAll will return a collection as large as the largest input, some results may contain undefined values.
Expand All @@ -438,7 +438,7 @@ zipWith<Z>(zipper: (...values: Array<unknown>) => Z, ...collections: Array<Colle
<Repl
defaultValue={`const a = List([ 1, 2, 3 ]);
const b = List([ 4, 5, 6 ]);
const c = a.zipWith((a, b) => a + b, b);`}
a.zipWith((a, b) => a + b, b);`}
/>

<MemberLabel label="shuffle()" />
Expand Down Expand Up @@ -531,7 +531,7 @@ Note: This is not a lazy operation.
Map({ v: 0 }),
Map({ v: 2 })
])
const groupsOfMaps = listOfMaps.groupBy(x => x.get('v'))`}
listOfMaps.groupBy(x => x.get('v'))`}
/>

## Conversion to JavaScript types
Expand Down