program to check if input string is valid anagram #260
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| import java.util.HashMap; | ||
| import java.util.Map; | ||
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| /** | ||
| * Created by Dungeoun on 10/2/16. | ||
| */ | ||
| public class Solution { | ||
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| public static int longestPalindrome(String s) { | ||
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| HashMap<Character, Integer> hash1 = new HashMap<>(); | ||
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| int length =0; | ||
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| for(int i = 0; i<s.length(); i++){ | ||
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| if(hash1.containsKey(s.charAt(i))==false){ | ||
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| hash1.put(s.charAt(i), 1); | ||
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| } | ||
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| else{ | ||
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| hash1.put(s.charAt(i), hash1.get(s.charAt(i))+1); | ||
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| } | ||
| } | ||
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| for(Map.Entry<Character,Integer> entry: hash1.entrySet()){ | ||
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| if(entry.getValue()%2 == 0){ | ||
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| length = length + entry.getValue(); | ||
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| } | ||
| else if(entry.getValue()%2 != 0){ | ||
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| length = length + entry.getValue()-1; | ||
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| } | ||
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| } | ||
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| if(s.length()>length) { | ||
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| return length + 1; | ||
| } | ||
| else return length; | ||
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| } | ||
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| public static void main(String []args){ | ||
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| int l = longestPalindrome("bb"); | ||
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| System.out.println(l); | ||
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| } | ||
| } |
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,89 @@ | ||
| import java.util.HashMap; | ||
| import java.util.Map; | ||
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| /** | ||
| * Created by Dungeoun on 10/2/16. | ||
| */ | ||
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| public class Solution { | ||
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| public static boolean isAnagram(String s, String t) { | ||
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There was a problem hiding this comment. Remove unnecessary empty lines. |
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| HashMap<Character, Integer> hash1 = new HashMap<>(); | ||
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| HashMap<Character, Integer> hash2 = new HashMap<>(); | ||
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| boolean a = false; | ||
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|
There was a problem hiding this comment. Put in some comments in your code. |
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| for (int i = 0; i < s.length(); i++) { | ||
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| if (hash1.containsKey(s.charAt(i)) == false) { | ||
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There was a problem hiding this comment. Instead of |
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| hash1.put(s.charAt(i), 1); | ||
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| } else { | ||
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| hash1.put(s.charAt(i), hash1.get(s.charAt(i)) + 1); | ||
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| } | ||
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| } | ||
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| for (int i = 0; i < t.length(); i++) { | ||
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| if (hash2.containsKey(t.charAt(i)) == false) { | ||
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There was a problem hiding this comment. Instead of |
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| hash2.put(t.charAt(i), 1); | ||
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| } else { | ||
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| hash2.put(t.charAt(i), hash2.get(t.charAt(i)) + 1); | ||
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| } | ||
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| } | ||
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| if(hash1.size()!=hash2.size()){ | ||
| a = false; | ||
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There was a problem hiding this comment. You can in this cases write |
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| } | ||
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| else if((hash1.size()==0 && hash2.size()==0) ) { | ||
| a = true; | ||
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There was a problem hiding this comment. Same thing as above. |
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| } | ||
| else if(hash1.size()!=hash2.size()){ | ||
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There was a problem hiding this comment. unnecessary. You has check this condition above, too. |
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| a = false; | ||
| } | ||
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| else { | ||
| for (Map.Entry<Character, Integer> entry : hash1.entrySet()) { | ||
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There was a problem hiding this comment. Instead of this monster. You can use |
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| if (hash2.containsKey(entry.getKey()) == true && hash2.get(entry.getKey()) == entry.getValue()) { | ||
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| a = true; | ||
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| } | ||
| else { | ||
| a = false; | ||
| break; | ||
| } | ||
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| } | ||
| } | ||
| return a; | ||
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| } | ||
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| public static void main( String []args){ | ||
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| boolean b = isAnagram("a","ab"); | ||
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There was a problem hiding this comment.
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| System.out.println(b); | ||
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| } | ||
| } | ||
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Please name your file according to the class name.