/***************************************************************************************

* *

* CODERBYTE BEGINNER CHALLENGE *

* *

* Letter Count I *

* Using the JavaScript language, have the function FirstFactorial(num) take the num *

* parameter being passed and return the factorial of it (ie. if num = 4, *

* return (4 * 3 * 2 * 1)). For the test cases, the range will be between 1 and 18. * *

* *

* SOLUTION *

* You can either use an iterative or recursive function to solve this challenge. *

* I am going to use an interative function. I am going to start with a value of 1 *

* for my total and then keep multiplying it by the next number until I reach num. *

* *

* This function needs to account for a possible outlier - One and Zero. *

* If num is 1 or 0 then the answer is 1. By setting tot to value of 1 at *

* initialization, then it guaranteees that 1 will be returned if num is ever 0 or 1. *

* Steps for solution *

* 1) Set var tot to 1. *

* 2) Loop from 2 to num and multiple tot by num to get new tot. *

* 3) Return tot for answer. *

* *

***************************************************************************************/

function LetterCountI(str) {

var words = str.split(" ");

var count = 0;

var word = "";

// code goes here

for (var i = 0; i < words.length; i++) {

var wordx = words[i];

var sum = 0;

for (var j = 0; j < words[i].length; j++) {

var letter = wordx[j];

for (var k = 0; k < wordx.length; k++) {

if ((j != k) && (letter === wordx[k])){

sum += 1;

}

}

}

if (sum > count) {

count = sum;

word = wordx;

}

}

if (count > 0) {

return word;

} else{

return "-1";

}

}