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Create Additive Persistence
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Additive Persistence

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/***************************************************************************************
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* *
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* CODERBYTE BEGINNER CHALLENGE *
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* *
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* Additive Persistence *
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* Using the JavaScript language, have the function AdditivePersistence(num) take the *
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* num parameter being passed which will always be a positive integer and return its *
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* additive persistence which is the number of times you must add the digits in num *
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* until you reach a single digit. For example: if num is 2718 then your program *
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* should return 2 because 2 + 7 + 1 + 8 = 18 and 1 + 8 = 9 and you stop at 9. * *
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* *
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* SOLUTION *
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* The challenge passes a string but it expects us to do Math on it so it needs to *
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* be converted to numbers. I will use the base 10 parameter of the toString() *
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* function and the map() function to convert each entry in the array to a Number. *
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* Then I am going to sum each entry in the array to get a total. I will repeat this *
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* until my total is a single digit number. The number of times I sum is returned *
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* as the answer. *
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* *
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* Steps for solution *
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* 1) Initialize vars sum and loop *
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* 2) Convert str to an array of numbers *
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* 3) Loop until the sum of digits in array is a single digit number *
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* 4) Return number of loops as answer *
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* *
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***************************************************************************************/
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function AdditivePersistence(num) {
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var sum, loop = 0;
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var val1 = num.toString(10).split("").map(function(t){return parseInt(t)});
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while (val1.length > 1) {
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sum = 0;
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val1.forEach( function(number) {
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sum = sum + number;
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});
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val1 = sum.toString(10).split("").map(function(t){return parseInt(t)});
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loop++;
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}
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return loop;
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}

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