/***************************************************************************************

* *

* CODERBYTE BEGINNER CHALLENGE *

* *

* Ex Oh *

* Using the JavaScript language, have the function ExOh(str) take the str parameter *

* being passed and return the string true if there is an equal number of x's and o's, *

* otherwise return the string false. Only these two letters will be entered in the *

* string, no punctuation or numbers. For example: if str is "xooxxxxooxo" then the *

* output should return false because there are 6 x's and 5 o's. *

* *

* SOLUTION *

* My solution accounts for the one outlier which is when the length of the string *

* is not even. Since the count of Xs and Os have to be equal then the only way for *

* this to happen is if the length of the string is an even number. I am going to *

* loop through the string and count every X. Then I am going to compare this count *

* to half the length of the string. If they are equal then you have equal number of *

* Xs and Os. *

* *

* Steps for solution *

* 1) Handle outlier first by seeing if str length is odd *

* 2) Loop thru each letter and count the number of Xs *

* 3) Compare count to 1/2 length of str and if same then return true *

* 4) Else return false *

* *

***************************************************************************************/

function ExOh(str) {

if (str.length % 2 === 1) {

return false;

}

else {

var tot = 0;

for (var i = 0; i < str.length; i++) {

if (str[i] === "x") {

tot++;

}

}

if (tot === (str.length / 2)) {

return true;

}

else {

return false;

}

}

}