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Commit 8330583

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Time: 45 ms (68.02%) | Memory: 16.8 MB (46.93%) - LeetSync
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def evaluateTree(self, root: Optional[TreeNode]) -> bool:
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#3 represnts and
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# 2 represnts OR
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# 1 means True
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#0 means False
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def helper(node):
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if not node.left and not node.right:
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return node.val == 1
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left = helper(node.left)
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right = helper(node.right)
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#post order
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if node.val == 3:
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return left and right
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if node.val == 2:
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return left or right
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return helper(root)
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