Subject

I parse an IP address with port to get a url, but ParseResult does not look right.

Environment

Describe your environment.
At least, paste here the output of:

OS Linux-5.10.0-17-amd64-x86_64-with-glibc2.31
>>> print("Python", platform.python_version())
Python 3.9.2

Steps to Reproduce

from urllib.parse import urlparse
urlparse('192.168.1.132:16992')

Expected Behavior

ParseResult(scheme='', netloc='192.168.1.132:16992', path='', params='', query='', fragment='')

Actual Behavior

ParseResult(scheme='192.168.1.132', netloc='', path='16992', params='', query='', fragment='')

I guess scheme should not be an IP address

This issue seems to be related: #38644