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| 1 | +# [807. Max Increase to Keep City Skyline](https://leetcode-cn.com/problems/max-increase-to-keep-city-skyline/) |
| 2 | + |
| 3 | +## 题目 |
| 4 | + |
| 5 | +There is a city composed of n x n blocks, where each block contains a single building shaped like a vertical square prism. You are given a 0-indexed n x n integer matrix grid where grid[r][c] represents the height of the building located in the block at row r and column c. |
| 6 | + |
| 7 | +A city's skyline is the the outer contour formed by all the building when viewing the side of the city from a distance. The skyline from each cardinal direction north, east, south, and west may be different. |
| 8 | + |
| 9 | +We are allowed to increase the height of any number of buildings by any amount (the amount can be different per building). The height of a 0-height building can also be increased. However, increasing the height of a building should not affect the city's skyline from any cardinal direction. |
| 10 | + |
| 11 | +Return the maximum total sum that the height of the buildings can be increased by without changing the city's skyline from any cardinal direction. |
| 12 | + |
| 13 | +**Example 1**: |
| 14 | + |
| 15 | + |
| 16 | + |
| 17 | + Input: grid = [[3,0,8,4],[2,4,5,7],[9,2,6,3],[0,3,1,0]] |
| 18 | + Output: 35 |
| 19 | + Explanation: The building heights are shown in the center of the above image. |
| 20 | + The skylines when viewed from each cardinal direction are drawn in red. |
| 21 | + The grid after increasing the height of buildings without affecting skylines is: |
| 22 | + gridNew = [ [8, 4, 8, 7], |
| 23 | + [7, 4, 7, 7], |
| 24 | + [9, 4, 8, 7], |
| 25 | + [3, 3, 3, 3] ] |
| 26 | + |
| 27 | +**Example 2**: |
| 28 | + |
| 29 | + Input: grid = [[0,0,0],[0,0,0],[0,0,0]] |
| 30 | + Output: 0 |
| 31 | + Explanation: Increasing the height of any building will result in the skyline changing. |
| 32 | + |
| 33 | +**Constraints:** |
| 34 | + |
| 35 | +- n == grid.length |
| 36 | +- n == grid[r].length |
| 37 | +- 2 <= n <= 50 |
| 38 | +- 0 <= grid[r][c] <= 100 |
| 39 | + |
| 40 | +## 题目大意 |
| 41 | + |
| 42 | +在二维数组grid中,grid[i][j]代表位于某处的建筑物的高度。 我们被允许增加任何数量(不同建筑物的数量可能不同)的建筑物的高度。 高度 0 也被认为是建筑物。 |
| 43 | + |
| 44 | +最后,从新数组的所有四个方向(即顶部,底部,左侧和右侧)观看的“天际线”必须与原始数组的天际线相同。 城市的天际线是从远处观看时,由所有建筑物形成的矩形的外部轮廓。 请看下面的例子。 |
| 45 | + |
| 46 | +建筑物高度可以增加的最大总和是多少? |
| 47 | + |
| 48 | +## 解题思路 |
| 49 | + |
| 50 | +- 从数组竖直方向(即顶部,底部)看“天际线”计算出topBottomSkyline |
| 51 | +- 从数组水平方向(即左侧,右侧)看“天际线”计算出leftRightSkyline |
| 52 | +- 计算grid中每个元素与对应的topBottomSkyline和leftRightSkyline中较小值的差值 |
| 53 | +- 统计所有差值的总和ans并返回 |
| 54 | + |
| 55 | +## 代码 |
| 56 | + |
| 57 | +```go |
| 58 | +package leetcode |
| 59 | + |
| 60 | +func maxIncreaseKeepingSkyline(grid [][]int) int { |
| 61 | + n := len(grid) |
| 62 | + topBottomSkyline := make([]int, 0, n) |
| 63 | + leftRightSkyline := make([]int, 0, n) |
| 64 | + for i := range grid { |
| 65 | + cur := 0 |
| 66 | + for _, v := range grid[i] { |
| 67 | + if cur < v { |
| 68 | + cur = v |
| 69 | + } |
| 70 | + } |
| 71 | + leftRightSkyline = append(leftRightSkyline, cur) |
| 72 | + } |
| 73 | + for j := range grid { |
| 74 | + cur := 0 |
| 75 | + for i := 0; i < len(grid[0]); i++ { |
| 76 | + if cur < grid[i][j] { |
| 77 | + cur = grid[i][j] |
| 78 | + } |
| 79 | + } |
| 80 | + topBottomSkyline = append(topBottomSkyline, cur) |
| 81 | + } |
| 82 | + var ans int |
| 83 | + for i := range grid { |
| 84 | + for j := 0; j < len(grid[0]); j++ { |
| 85 | + ans += min(topBottomSkyline[j], leftRightSkyline[i]) - grid[i][j] |
| 86 | + } |
| 87 | + } |
| 88 | + return ans |
| 89 | +} |
| 90 | + |
| 91 | +func min(a, b int) int { |
| 92 | + if a < b { |
| 93 | + return a |
| 94 | + } |
| 95 | + return b |
| 96 | +} |
| 97 | +``` |
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